@delete21/ts-serializer v2.2.1
TS Serializer provides
TypeScriptdecorators to help developers with serializing/deserializing TypeScript classes into and from JSON objects.
This project is a fork from dpopescu's project
Why?
The project is not maintained anymore and there are some feature and fixes that me and my team needed:
optionalproperty option, disscursed here issue 10 - commit here- fix to properties with falsy values such as
0(zero) andfalsethat should be valid - commit here
Installation
Using npm:
npm install --save @delete21/ts-serializer
Usage
You can find a codesandbox playground here!
TypeScript
Deserialization:
import {Serialize, SerializeProperty, Serializable} from '@delete21/ts-serializer';
@Serialize({})
class MyClass extends Serializable {
@SerializeProperty({
map: 'username'
})
public name:string;
}
let instance:MyClass = new MyClass();
console.log(instance.name); // Prints `undefined`
instance.deserialize({
username: 'Some Value'
});
console.log(instance.name); // Prints 'Some Value'Serialization:
import {Serialize, SerializeProperty, Serializable} from '@delete21/ts-serializer';
@Serialize({})
class MyClass extends Serializable {
@SerializeProperty({
map: 'username'
})
public name:string;
}
let instance:MyClass = new MyClass();
instance.name = 'Some Value';
console.log(instance.serialize()); // Prints {username:'Some Value'}JavaScript
Note: Although the library was designed to be used as a decorator in TypeScript, it doesn't matter that it can't be used in plain old JavaScript. The syntax can be a little messy but the result is the same.
Deserialization:
var Serialize = TSerializer.Serialize;
var SerializeProperty = TSerializer.SerializeProperty;
function MyClass(){
this.name;
}
Serialize({})(MyClass);
SerializeProperty({
map: 'username'
})(MyClass.prototype, 'name');
var instance = new MyClass();
console.log(instance.name); // Prints `undefined`
instance.deserialize({
username: 'Some Value'
});
console.log(instance.name); // Prints 'Some Value'Serialization:
var Serialize = TSerializer.Serialize;
var SerializeProperty = TSerializer.SerializeProperty;
function MyClass(){
this.name = 'Some Value';
}
Serialize({})(MyClass);
SerializeProperty({
map: 'username'
})(MyClass.prototype, 'name');
var instance = new MyClass();
console.log(instance.serialize()); // Prints {username:'Some Value'}Library Options
The library allows you to pass different serialization/deserialization options both on class level and on property level.
Class Options
root
When you want to deserialize just a child object from the JSON you can use the root option.
@Serialize({
root: 'childObject'
})
class MyClass extends Serializable {
@SerializeProperty({})
public name:string;
}
let instance:MyClass = new MyClass();
instance.deserialize({
childObject: {
name: 'Some Value'
}
});
console.log(instance.name); // Prints 'Some Value'Property Options
root
The root option can also be used on a property.
Note: If
rootis already specified at class level the value is inherited to all class properties. If you want to override this, you can use hte.value. In this case, the property will be mapped up one level.
@Serialize({})
class MyClass extends Serializable {
@SerializeProperty({
root: 'childObject'
})
public name:string;
}
let instance:MyClass = new MyClass();
instance.deserialize({
childObject: {
name: 'Some Value'
}
});
console.log(instance.name); // Prints 'Some Value'map
When the property name in the JSON doesn't match with your class properties, the map option can be used. This option maps a property from the JSON with a different property from your class.
@Serialize({})
class MyClass extends Serializable {
@SerializeProperty({
map: 'username'
})
public name:string;
}
let instance:MyClass = new MyClass();
instance.deserialize({
username: 'Some Value'
});
console.log(instance.name); // Prints 'Some Value'list
The list option can be used when the JSON property value is a list of items.
@Serialize({})
class MyClass extends Serializable {
@SerializeProperty({
list: true
})
public items:string[];
}
let instance:MyClass = new MyClass();
instance.deserialize({
items: ['a', 'b', 'c']
});
console.log(instance.items); // Prints ['a', 'b', 'c']type
When you want to use non-primitive types for deserialization use the type option.
Note: The
typeobject should also be aSerializableobject.
@Serialize({})
class User extends Serializable {
@SerializeProperty({})
public firstName:string;
@SerializeProperty({})
public lastName:string;
}
@Serialize({})
class Profile extends Serializable {
@SerializeProperty({
type: User
})
public user:User;
}
let instance:Profile = new Profile();
instance.deserialize({
user: {
firstName: 'John',
lastName: 'Doe'
}
});
console.log(instance.user.firstName); // Prints 'John'
console.log(instance.user.lastName); // Prints 'Doe'optional
The optional option can be used when the property or the value may not exist.
@Serialize({})
class User extends Serializable {
@SerializeProperty({})
public name:string;
@SerializeProperty({
optional: true
})
public age:number;
}
@Serialize({})
class Profile extends Serializable {
@SerializeProperty({
type: User
})
public user:User;
}
let instance:Profile = new Profile();
instance.deserialize({
user: {
firstName: 'John',
}
});
console.log(instance.user.firstName); // Prints 'John'
console.log(instance.user.age); // Prints 'null'Contribute
You can help improving this project sending PRs and helping with issues.
Also you can ping me at Twitter