1.3.0 • Published 1 year ago

@kartjim/linkedlist v1.3.0

Weekly downloads
-
License
MIT
Repository
github
Last release
1 year ago

@kartjim/linkedlist

LinkedList and DoubleLinkedList implementation in JavaScript

学习项目,参考自:datastructures-js/linked-list

install

npm i @kartjim/linkedlist

require

const {
  LinkedList,
  DoubleLinkedList,
  LinkedListNode,
  DoubleLinkedListNode,
} = require('@kartjim/linkedlist');

import

import {
  LinkedList,
  DoubleLinkedList,
  LinkedListNode,
  DoubleLinkedListNode,
} from '@kartjim/linkedlist';

LinkedList API

use

constructor

const root = new LinkedList();

insertHead

inserts a node at the beginning of the list.
time complexity: $O(1)$

root.insertHead(12)
console.log(root.insertHead(11).getCount()) // 11
console.log(root.getCount()) // 2
console.log(root.toArray()) // [11, 12]

insertTail

add a node at the end of the LinkedList.
time complexity: min $O(1)$ , max $O(n)$

let saveNode = root.insertTail(21);
root.insertTail(22, saveNode);
console.log(root.getCount()) // 4
console.log(root.toArray()) // [11, 12, 21, 22]

insertAt

add a node at a specify location.
time complexity: $O(n)$

root.insertAt(2, 31)
console.log(root.getCount()) // 5
console.log(root.toArray()) // [11, 12, 31, 21, 22]

getHead

get the head node.

console.log(root.getHead().getValue()) // 11

getCount

get the nodes count.

console.log(root.getCount()) // 5

isEmpty

check if the likedlist is empty.

console.log(root.isEmpty()) // false

toArray

convert linkedlist into Array.
time complexity: $O(n)$

console.log(root.toArray()) // [11, 12, 31, 21, 22]

reverse

reverse the linkedlist.

root.reverse();
// [12, 13, 42, 43]
// => 
// [43, 42, 13, 12]

removeHead

remove a node at the beginnig of the LinkedList.
time complexity: $O(1)$

root.removeHead()
console.log(root.getHead().getValue()) // 12

removeTail

remove a node at the end of the LinkedList.
time complexity: $O(n)$

root.removeTail()
console.log(root.getCount()) // 3
console.log(root.toArray()) // [12, 31, 21]

removeAt

remove a node at a specify location.

First (head) node is at position 0.

time complexity: $O(n)$

root.removeAt(1)
console.log(root.getCount()) // 2
console.log(root.toArray()) // [12, 21]

removeEach

remove nodes based on a callback.

root.insertTail(41); root.insertTail(42);
console.log(root.toArray()) // [12, 21, 41, 42]
root.removeEach(
    (n) => n.getValue() < 41 && n.getValue() > 12
)
console.log(root.toArray()) // [12, 41, 42]

forEach

Traverses the list from beginning to end. The original root will not be changed.

const arr = [];
root.forEach((node) => {
    const val = node.getValue();
    if (val > 40) arr.push(val);
});
console.log(arr) // [41, 42]

find

find the first node in the linkedlist based on a callback, get null if nothing is found. It also accepts a second param as the starting node to start searching from.

const num1 = root.find((n) => n.getValue() === 41);
const num2 = root.find((n) => n.getValue() === 21);
console.log(num1.getValue()) // 41
console.log(num2) // null

filter

filter the linkedlist based on a callback, return a new LinkedList.

console.log(root.filter((n) => n.getValue() > 40).toArray()) // [41, 42]

map

map the linkedlist\' value based on a callback, return a new LinkedList.

root.toArray()    // [12, 41, 42]);
const newRoot = root.map((n) => n % 2);
newRoot.toArray()  // [0, 1, 0]
root === newRoot  // false

reduce

reduce the linkedlist based on a callback, return value.

const newRoot = root.reduce((pre, cur) => cur + pre, 0); 
// [12, 41, 42] => 95

insertBefore

Add a node before the head node.
time complexity: $O(n)$

const Twelve = root.find((n) => n.getValue() === 12);
root.insertBefore(Twelve, 1)
console.log(root.toArray()) // [1, 12, 41, 42] 

insertAfter

Add a node after the giving node. time complexity: $O(1)$

const Thirteen = root.find((n) => n.getValue() === 13);
root.insertAfter(Thirteen, 14)
// [1, 12, 13, 41, 42] 
// => 
// [1, 12, 13, 14 41, 42] 

removeBefore

remove nodes before the giving node.
time complexity: $O(n)$

const FortyOne = root.find((n) => n.getValue() === 41);
root.removeBefore(FortyOne)
// [12, 13, 14, 41, 42, 43]
// => 
// [12, 13, 41, 42, 43]

removeAfter

remove nodes after the giving node.
time complexity: $O(1)$

const Thirteen = root.find((n) => n.getValue() === 13);
root.removeAfter(Thirteen)
// [12, 13, 41, 42, 43]
// => 
// [12, 13, 42, 43]

clear

clear the linkedlist.

root.clear();
console.log(root.getCount()) // 0
console.log(root.getHead()) // null

LinkedList.fromArray

create a LinkedList from an Array.

const root2 = LinkedList.fromArray([1, 2, 3, 4, 5]);

LinkedListNode

setValue

set the value of the node.

getValue

get the value of the node.

setNext

set the next node.

getNext

get the next node.

hasNext

checks if node has a next node.

DoubleLinkedList API

use

constructor

const root = new DoubleLinkedList();

insertHead

inserts a node at the beginning of the DoubleLinkedList.
time complexity: $O(1)$

root.insertHead(2)
console.log(root.insertHead(1).getCount()) // 1
console.log(root.getCount()) // 2
console.log(root.toArray()) // [1, 2]

insertTail

add a node at the end of the DoubleLinkedList.
time complexity: $O(1)$

root.insertTail(3)
console.log(root.getCount()) // 3
console.log(root.toArray()) // [1, 2, 3]

insertAt

add a node at a specific position.
time complexity: $O(n)$

root.insertAt(0, 0)
root.insertAt(4, 4)
root.insertAt(2, 21)
console.log(root.getCount()) // 6
console.log(root.toArray()) // [0, 1, 21, 2, 3, 4]

getCount

get the count of the DoubleLinkedList.

console.log(root.getCount()) // 6

toArray

convert the doubleLinkedList into an array.

console.log(root.toArray()) // [0, 1, 21, 2, 3, 4]

isEmpty

check if the DoubleLinkedList is empty.

console.log(root.isEmpty()) // false

getHead

get the head of doubleLinkedList.

console.log(root.getHead().getValue()) // 0

getTail

get the tail of doubleLinkedList.

console.log(root.getTail().getValue()) // 4

forEach

Traverses the list from beginning to end.

const arr = [];
root.forEach((node) => {
  const val = node.getValue();
  if (val > 9) arr.push(val);
});
console.log(arr) // [21]

removeHead

remove the head of the DoubleLinkedList.
time complexity: $O(1)$

console.log(root.removeHead().getValue()) // 0
console.log(root.toArray()) // [1, 21, 2, 3, 4]

removeTail

remove the tail of the DoubleLinkedList.
time complexity: $O(1)$

console.log(root.removeTail().getValue()) // 4
console.log(root.toArray()) // [1, 21, 2, 3]

removeAt

remove a node at a specific position.
time complexity: $O(n)$

console.log(root.removeAt(2).getValue()) // 2
console.log(root.toArray()) // [1, 21, 3]

find

find the first node in the DoubleLinkedList based on a callback, get null if nothing is found. It also accepts a second param as the starting node to start searching from.

const num2 = root.find((n) => n.getValue() === 21);
console.log(num2.getValue()) // 21

filter

filter the linkedlist based on a callback, return a new LinkedList.

console.log(root.filter((n) => n.getValue() > 20).toArray()) // [21]

clear

clear the linkedlist.

root.clear();
console.log(root.getCount()) // 0
console.log(root.isEmpty()) // true

DoubleLinkedList.fromArray()

create a LinkedList from an Array.

console.log(DoubleLinkedList.fromArray(['a', 'b', 'c', 'd']).toArray())
// ['a', 'b', 'c', 'd']

DoubleLinkedListNode

setValue

set the value of the node.

getValue

get the value of the node.

setPrev

set the previous node.

getPrev

get the previous node.

hasPrev

check if node has a previous node.

setNext

set the next node.

getNext

get the next node.

hasNext

check if node has a next node.

License

MIT

1.3.0

1 year ago

1.2.3

1 year ago

1.2.2

1 year ago

1.2.1

1 year ago