1.0.0 • Published 2 years ago
@pedroagont/lotide v1.0.0
Lotide
A mini clone of the Lodash library for educational purposes.
Purpose
BEWARE: This library was published for learning purposes. It is not intended for use in production-grade software.
This project was created and published by me as part of my learnings at Lighthouse Labs.
Usage
Install it:
npm install @username/lotide
Require it:
const _ = require('@username/lotide');
Call it:
const results = _.tail([1, 2, 3]) // => [2, 3]
Documentation
The following functions are currently implemented:
head(array)
: Returns a the element at index 0 of the argument array.tail(array)
: Returns a new array without the one at index 0 in the argument array.middle(array)
: Returns a new array with the element or elements at the hallway index or indexes in an array of an odd or of an even number of elements, respectively.without(source, itemsToRemove)
: Returns a new array from an argument array with elements removed per the other argument array provided.eqArrays(array1, array2)
: Returns true for two identical arrays, false otherwise.flatten(array)
: Returns a new array with elements of children arrays (one level deep) expanded into the outer array in addition to all other elements of non-objects in the outer array.countOnly(allItems, itemsToCount)
: Returns an object with keys representing the elements needed to account for and values representing their number of occurrences in an array.countLetters(string))
: Returns an object with keys representing the characters and values representing their number of occurrences in a string.letterPositions(string)
: Returns an object with keys representing the characters and values, as arrays of numbers representing their indices in a string.findKeyByValue(object, value)
: Returns key in an object, if the key contains the value specified in the corresponding argument, undefined otherwise.eqObjects(object1, object2)
: Returns true for two identical objects, false otherwise.isPalindrome(string)
: Returns true if a string contains the same characters from left to right and right to left, false otherwise.
1.0.0
2 years ago