@shlappas/heap v1.0.5
Heap
A simple module to maintain a binary heap.
Installation
yarn add @shlappas/heapUsage
Similar to the python heapq
module, the actual datastructure is just a normal array!
const heap = [9, 7, 6, 4, 1]
heapify(heap) // now heap is a min-heap!Calling heapify makes sure that we can do the following:
heap[0]is the minimum element in the array.- Calling any of
heappush,heappop,heappushpop, orheapreplaceachieves the intended result. For more information, check out the docs. Built withtypedoc!
Default Compare
In keeping with the builtin Array.prototype.sort() function, the default
behaviour of the heap methods is to compare values based on their string
representation.
const heap = [10, 100, 5, 50]
heapify(heap) // [10, 100, 5, 50], since '10' < '5' etc.If this is not intended, there are two options:
Pass a custom
comparefunction to each individual call:import { heapify, heappop } from '@shlappas/heap' const compare = (a: number, b: number) => a - b const heap = [10, 100, 5, 50] heapify(heap, compare) // [5, 50, 10, 100] heappop(heap, compare) // 5 and the remaining heap is [10, 50, 100]Redefine the heap methods with a fixed
comparefunction:const { useHeap } from '@shlappas/heap' const { heapify, heappop } = useHeap<number>((a, b) => a - b) const heap = [10, 100, 5, 50] heapify(heap) // [5, 50, 10, 100] heappop(heap) // 5 and the remaining heap is [10, 50, 100]
Examples
N Largest
We can find the n largest elements of an array*:
function nLargest<T, N extends number>(arr: T[], n: N): Tuple<T, N> {
const result: T[] = []
for (let i = 0; i < n; i++) {
result.push(arr[i])
}
heapify(result)
for (let i = n; i < arr.length; i++) {
heappushpop(result, arr[i])
}
return result as Tuple<T, N>
}*Shameless plug: For the Tuple type, consider using
tuple-type!*
Merge
We can merge a bunch of already sorted arrays*:
function merge(compare, ...preSorted) {
const result = []
const status = [...zip(repeat(0), preSorted)]
const { heapify, heappop, heapreplace } = useHeap(([i1, l1], [i2, l2]) => {
return compare(l1[i1], l2[i2])
})
heapify(status)
while (status.length) {
const [idx, list] = status[0]
result.append(list[idx])
idx += 1
if (idx === list.length) {
heappop(status)
} else {
heapreplace(status, [idx, list])
}
}
return result
}*Shameless Plug 2: Electric Boogaloo: For the zip, filter and repeat
functions (along with some other nice tools for iterators), consider using
@shlappas/itertools!*
* I reccomend not using these implementations verbatim; some heavy assumptions
are made in the name of brevity. Check out examples for some safer
implementations.