0.0.1 • Published 11 years ago
a.require v0.0.1
a.require for Node.js
Require manager for Node.js. Can execute same function as system require
and some else
Usage
Install with npm
npm install a.require
Configurate at first
var _require = require('a.require');
_require.init({root: __dirname});
Try it
Load Node.js module
var fs = _require('fs')
Load javascript file from root location
var simple = _require('./simple')
For example you has some file structure like this
application$ /private/tmp
├── app
│ ├── helpers
│ ├── modules
│ │ ├── core
│ │ │ └── models
│ │ │ └── settings.js
│ │ └── frontend
│ │ ├── controllers
│ │ │ └── index.js
│ │ ├── dao
│ │ │ └── posts.js
│ │ ├── models
│ │ │ └── posts.js
│ │ └── modules
│ │ ├── admin
│ │ │ ├── controllers
│ │ │ │ └── index.js
│ │ │ └── models
│ │ │ └── profile.js
│ │ └── auth
│ │ └── controllers
│ │ └── users.js
│ └── utils
│ └── request.js
└── config
└── app.yaml
Get index.js
controller from frontend
var indexFrontend = _require("controller:app.frontend:index")
Get post.js
model from frontend
var postModelFrontend = _require("model:app.frontend:posts")
Get posts.js
dao from frontend
_require.init({names: {'dao': 'dao'}});
var postsDAOFrontend = _require("dao:app.frontend:posts")
Get index.js
controller from frontend/admin
var indexAuthFrontend = _require("controller:app.frontend.auth:index")
Get request
from utils
var request = _require("app:./utils/request")
var request = _require("./app/utils/request")
Extra
Get full path to file
var fullname = _require.path("config:app.yaml");
License
May be freely distributed under the MIT license
See LICENSE
file
Copyright (c) 2013 - Sumskoy Andrew andy@away.name
0.0.1
11 years ago