args-filter v1.0.3

Issue : needing to verify the parameters in javascript functions in an effective and clean manner.

Lets say we have the following function.

var foo = function(num){ return num / 3; }

We are assuming that num is a number, and currently we have no default values and no type checking so this will totally work foo({}) or foo(foo) or foo('anything') or even foo() and undefined / 3 is an error. This is a simple version of this but it shows the issue.

We have methods of overcoming this such as the following.

method 1

var foo = function(num){ if(num){ num = 1; } return num / 3; }

method 2

var foo = function(num){ num = num | 1; return num / 3; }

These methods do the same thing but what if num was 0 both would reassign it to 1 also if it is a string it would not catch this. This catches the edge cases and also verifies the type of data.`

method 3

var foo = function(num){ if(typeof num !== 'number'){ num = 1; } return num / 3; }

Do this methods scale well

var foo = function(num, str, arr, obj, func){ var boo = [] //holder for all values

if(typeof num !== 'number'){
	num = 1;
}
if(typeof str !== 'string'){
	str = '';
}
if(Array.isArray(arr)){
	arr = [];
}
if(typeof obj !== 'object'){
	obj = {};
}
if(typeof func !== 'function'){
	func = function(){};
}
boo.push(num, str, arr, obj, func);
return boo

}

This take a good chunk of code just to verify types and set defaults. What if we did the same code but this way

var foo = function(num, str, arr, obj,func){ arguments.types(1,'',[],{},function(){}); return arguments.toArray(); }

what if we didn't care about types we just wanted defaults just in case they were undefined.

var foo = function(num, str, arr, obj,func){ arguments.defaults(1,'',[],{},function(){}); return arguments.toArray(); }

This does convert the source variables so when you call num it will be num not arguments0

var foo = function(num){ arguments.defaults(1); return num + 1; }

var bar = function(num){ arguments.types(1); return num + 1; }

foo() would be 2 foo('') would be '1' bar() would be 2 bar('') would be 2