Boxset NPM | npm.io

Lazily evaluated set operations for all collections

Problem: Set and Map are fantastic additions to JavaScript, providing better capabilities and performance for common tasks. However, their APIs are threadbare — they don’t provide methods for even merging two sets!

Boxset allows you to work with data structures such as Set, Map, Array, Object FormData, and perform unions, intersections, differences, and interoperate between them.

import {
  source,
  complement,
  union,
  difference,
  intersection,
  create,
} from 'boxset';

const dramas = source(['The Americans', 'Breaking Bad', 'The Sopranos']);
const comedies = source(['Flight of the Conchords']);

const shows = union(dramas, comedies);

shows('The Americans'); // true
shows('Flight of the Conchords'); // true
shows('The Wire'); // false

const showsSet = create(shows, Set);
// Set ['The Americans', 'Breaking Bad', 'The Sopranos', 'Flight of the Conchords']

const startingWithThe = (title: string) => title.startsWith('The ');
const showsStartingWithThe = intersection(shows, startingWithThe);

const showsStartingWithTheSet = create(showsStartingWithThe, Set);
// Set ['The Americans', 'The Sopranos']

Installation

npm add parcook

Docs

Types

export interface Source<I, O> {
  (input: I): O;
}

export interface NotFound {
  (): undefined | null | false;
}

export type Contains<I> = Source<I, boolean>;

export interface SourceIterable<I, O>
  extends Source<I, O>,
    Iterable<[I, O]>,
    NotFound {}

`source(collection)`

Create a SourceIterable with the given collection, which may be a Set, Array, Map, FormData, or plain object.

The return types for a given input are as follows:

Set<A> -> SourceIterable<A, boolean>
Array<A> -> SourceIterable<A, boolean>
Map<K, V> -> SourceIterable<K, V>
FormData -> SourceIterable<string, string>
Record<K, V> (plain object) -> SourceIterable<K, V>

Collections are referenced not copied, so passing a collection to source() and then making changes to the original collection will be reflected.

import { source } from 'boxset';

const citrusFruitCosts = source(new Map([['orange', 3.00], ['lemon', 4.50]]));
const otherFruitCosts = source({ apple: 2.50, pear: 3.00 });
const citrusFruits = source(new Set(['orange', 'lemon']));
const greenFruits = source(['apple', 'pear']);

`union(a, b)`

Combines two sources into a union.

The sources are referenced not copied. Source a is checked before checking b.

The result will be a SourceIterable if both sources were iterable, otherwise a non-iterable Source.

import { source, union } from 'boxset';

const citrusFruitCosts = source(new Map([['orange', 3.00], ['lemon', 4.50]]));
const otherFruitCosts = source({ apple: 2.50, pear: 3.00 });
const fruitCosts = union(citrusFruitCosts, otherFruitCosts);

const fruitCostsMap = new Map(fruitCosts);
// new Map([['orange', 3.00], ['lemon', 4.50], ['apple', 2.50], ['pear', 3.00]])

const fruitCostsObject = Object.fromEntries(fruitCosts);
// { orange: 3.00, lemon: 4.50, apple: 2.50, pear: 3.00 }

`difference(a, b)`

Creates a SourceIterable with all the elements of a except those that are in b.

For example, we could create a source from a Map omitting entries from a Set like so:

import { source, difference } from 'boxset';

const fruitCosts = source(new Map([['apple', 2.50], ['orange', 3.00], ['lemon', 4.50], ['pear', 3.00]]));
const citrusFruits = source(new Set(['orange', 'lemon']));
const nonCitrusFruitCosts = difference(fruitCosts, citrusFruits);
const nonCitrusFruitCostsMap = new Map(nonCitrusFruitCosts);
// new Map([['apples', 2.50], ['pears', 3.00]]);

We could do the same for an object omitting keys from an Array:

import { source, difference } from 'boxset';

const fruitCosts = source({ apple: 2.50, orange: 3.00, lemon: 4.50, pear: 3.00 });
const citrusFruits = source(['orange', 'lemon']);
const nonCitrusFruitCosts = difference(fruitCosts, citrusFruits);
const nonCitrusFruitCostsObject = Object.fromEntries(nonCitrusFruitCosts);
// { apple: 2.50, pear: 3.00 }

`intersection(a, b)`

Creates a SourceIterable with all the elements that are both in a and b.

For example, we could create a source from a Map keeping entries within a Set like so:

import { source, intersection } from 'boxset';

const fruitCosts = new Map([['apple', 2.50], ['orange', 3.00], ['lemon', 4.50], ['pear', 3.00]]);
const citrusFruits = new Set(['orange', 'lemon']);
const citrusFruitCosts = intersection(source(fruitCosts), source(citrusFruits));
const citrusFruitCostsMap = new Map(citrusFruitCosts);
// new new Map([['oranges', 3.00], ['lemons', 4.50]]);

`complement(a)`

Returns the opposite of what a would have returned. If a given key returned true for a, then the result would return false. And if a given key returned false for a, then the result would return true.

import { source, complement } from 'boxset';

const citrusFruits = new Set(['orange', 'lemon']);
const isCitrusFruit = source(citrusFruits);
const isNotCitrusFruit = complement(isCitrusFruit);

isCitrusFruit('orange'); // true
isNotCitrusFruit('orange'); // false
isCitrusFruit('peach'); // false
isNotCitrusFruit('peach'); // true

`single(key, value?)`

Creates a SourceIterable with the given key and optional value. If value is not provided, then the result will be a set containing just the key.

import { single } from 'boxset';

const pair = single('PI', 3.14159);
pair('PI'); // 3.14159
pair('TAU'); // undefined

const setOfOne = single('some key');
setOfOne('some key'); // true
setOfOne('any other key'); // false

Constants

`emptySet`

A collection that contains no keys, i.e. it returns false for any key.

`universalSet`

A collection that contains all keys, i.e. it returns true for any key.

import { emptySet, universalSet } from 'boxset';

emptySet('any key'); // false
emptySet(42); // false

universalSet('any key'); // true
universalSet(42); // true

This project was bootstrapped with TSDX.

Local Development

`npm start`

Runs the project in development/watch mode. Your project will be rebuilt upon changes. TSDX has a special logger for you convenience. Error messages are pretty printed and formatted for compatibility VS Code's Problems tab.