0.0.3 • Published 5 years ago

clapient v0.0.3

Weekly downloads
3
License
MIT
Repository
github
Last release
5 years ago

clapient

Create your API client in typescript with clapient.

clapient uses axios as its HTTP client

Why clapient?

While developing frontent for webapps(like Angular), we use normal http client library to send AJAX requests. The structure of the AJAX client is nothing but a class with some methods that corresponds to the API endpoints we use. Most of the time we do not care about these methods but it seriously jeopardize the future development because changing a small chunk of code generates a series of errors that we do not understand.

Here, clapient can provide not only a safer development practice but also leads to less erroneous AJAX calls to your API backend.

Install

$ npm install clapient

Concept

APIClient

The APIClient class is used to define api client both by extending or instantiating.

Define Routes

Routes are basically object with key:value pair(in TypeScript's standard library, there is a type called Record) like following:

{
    getusers: 'https://reqres.in/api/users',
    getauser: 'https://reqres.in/api/users/{id}'
}

Use curly braces for parameters in your request url.

You can define routes via any of the following:

  • Via constructor
  • Via setRoutes() method

Request types

  • getRequest(name: string, requestParams?: any, queryParams?: any)
  • postRequest(name: string, payload: any, requestParams?: any, queryParams?: any)
  • putRequest(name: string, payload: any, requestParams?: any, queryParams?: any)
  • patchRequest(name: string, payload: any, requestParams?: any, queryParams?: any)
  • deleteRequest(name: string, payload: any, requestParams?: any, queryParams?: any)
  • headRequest(name: string, requestParams?: any, queryParams?: any)

Parameters

  • name - Key name of a route.
  • requestParams - Object with key : value pair. Example: { id: 2 }
  • queryParams - Similar to requestParams
  • payload - JSON object to be sent.

Note: when withFile() is used, FormData will be sent instead of normal json object.

Usage

import { APIClient } from 'clapient';

interface User{
    id: number;
    first_name: string;
    last_name: string;
}

let api: APIClient = new APIClient({
    getusers: 'https://reqres.in/api/users',
    getauser: 'https://reqres.in/api/users/{id}'
});

api
.getRequest('getusers', null, { page: 2 })//queryParams
.then((response)=>{
    let users: User[] = response.data.data;
    console.log(users[1].first_name);
})
.catch((e)=>{
    console.log(e.responseJSON)
});

api
.getRequest('getauser', { id: 2 })//requestParams
.then((response)=>{
    let user: User = response.data.data;
    console.log( user.first_name );
})
.catch((e)=>{
    console.log(e.responseJSON)
});

File Upload

Use withFile() method to indicate that the content type of the following request will be multipart/form-data

api
.withFile()
.postRequest('endpointX', {
    first_name: "Peter Parker",
    photo: yourfileobject
})
.then((response)=>{
    console.log( response.data );
})
.catch((e)=>{
    console.log(e.responseJSON)
});

Transform data before sending

Use withTypeTransform() method to transform some specific value in the input json. Example:

api
.withTypeTransform('personal_details.info.dob', v =>moment(v).format('YYYY-MM-DD') )
.postRequest('save_user', data)
0.0.3

5 years ago

0.0.2

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0.0.1

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