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gmail_password_hacking_software_v289_license_key_19_free__on v1.0.0
Gmail Password Hacking Software V289 License Key 19 ((FREE))
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the first attack method based on hash collisions is the so-called rainbow attack. we can now associate an entirely different password with f. let f(b)=f be a function from the alphabet a to itself, where a is the alphabet used in the password system and where b in f(b) is any element in a. if we iterate f(b), we can eventually find f (b1) = f(b), f(b2) = f(b2), and so on. in other words, the sequence b1, b2,.. bn gives us a family of letters in f for which there is a hash collision. if p is the string of letters used in f, it is possible, once we obtain the first collision, to deduce the entire password.
among the possible attack methods, the rainbow attack is of particular interest. for example, if we know that f(b) = f(b2) = f(b3) =.. = f(bn) = f(bn+1), that is, we have n+1 pairs of colliding hashes and that f(b) is the same as f(b2) and f(b2) as f(b3). and that f(bn) = f(bn+1), we can deduce that p = p(2) = p(3). and that p = p(n). in other words, f(b) is a permutation of the alphabet, and the problem is reduced to cracking a password if we know a few permutations. (it is also possible to stop the iterative process sooner: just because we have f(b) = f(b2) does not mean that p(n) = p(n+1). likewise, in the sequence (a, b, c, a+b, b+c, a+b+c) it is not enough to know only that a+b and b+c are equal to a+b+c.
hash functions have been used for decades in a variety of applications including the authentication of user names and passwords. our h(f) represents a fingerprint of f in a way that is hard to forge, and so a password is stored in the form of a hash of its correct value rather than as f itself. the hash function can be used as a stand-alone tool to test whether two data are identical. it can also be used to compare a password or user name to a stored value. 84d34552a1
1.0.0
2 years ago