gulpclass v0.2.0
Make a beautiful class-based gulpfiles with Typescript and Gulpclass
Allows to create a gulp files in classes, each method of which can be a gulp task.
Installation
Install module:
npm install gulpclass --save-dev
Use typings to install all required definition dependencies.
typings install
Usage
Create a
gulpfile.ts
and describe your tasksimport {Gulpclass, Task, SequenceTask} from "gulpclass"; import * as gulp from "gulp"; import * as del from "del"; @Gulpclass() export class Gulpfile { @Task() // return promise to indicate your task completion clean() { // del module returns promise for you automatically return del("./dist/**"); } @Task() // or use provided callback instead clean(cb: Function) { return del("./dist/**", cb); } @Task() copyFiles() { // don't forget to return stream from your task function return gulp.src(["./README.md"]) .pipe(gulp.dest("./dist")); } @Task("copy-source-files") // you can specify custom task name if you need copySourceFiles() { return gulp.src(["./src/**.js"]) .pipe(gulp.dest("./dist/src")); } @SequenceTask() // this special annotation using "run-sequence" module to run returned tasks in sequence build() { return ["copyFiles", "copy-source-files"]; } // list of dependencies could be specified as a second argument to trigger other tasks // the example below is equivalent to `gulp.task("default", ["build"]);` @Task("default", ["build"]) defaultTask() { // using "defaultTask", because "default" is a reserved keyword in ES2015 } }
How to run
First option. Use ts-node
Install ts-node, it supports running gulp tasks directly using gulp command
Second option. If you don't want to use ts-node
There is a caveat of using gulp and typescript together. The problem is that when you run your
gulp
commands in console, gulp cannot read your tasks from your typescript code - it can read only fromgulpfile.js
. But there is a simple workaround - you can create a gulpfile.js, compile and execute typescript on-the-fly.Create a gulpfile.js and put there this piece of code:
eval(require("typescript").transpile(require("fs").readFileSync("./gulpfile.ts").toString()));
This piece of code reads your gulpfile.ts contents, and asks typescript to transpile it on-the-fly and executes transpiled result as javascript.
(you need to run
npm install typescript --save-dev
if you dont have typescript package installed)Please note that if you are NOT using
outDir
in typescript compile options, you may have problems if your gulpclass file is namedgulpfile.ts
typescript compiler will try to compile it togulpfile.js
, and will override code you added to gulpfile.js. Solution is simple - rename yourgulpfile.ts
. You can call it as you wish, for example you can call itgulpclass.ts
.Alternative approaches
Alternative approaches depend on which tsconfig configuration you use. These examples assume that you are using
"outDir": "build"
as a directory to where files are compiled:- create
gulpfile.js
and put thererequire("build/gulpfile")
- or run gulp in cmd with extra parameters:
gulp --gulpfile build/gulpfile.js --cwd .
Benefits of this apporach is that you can use debug your gulp classes in IDEs.
- create
FAQ
- How to load tasks from multiple files?
Edit your gulpfile.js
and change it following way:
const files = [
"./othertask.ts",
"./gulpfile.ts"
];
files.forEach(function(file) { eval(require("typescript").transpile(require("fs").readFileSync(file).toString())) });
- How to use task dependencies?
Simple use second argument of the @Task
decorator:
@Task("someTask", ["clean", "compile"])
someTask() {
return doSomething();
}
- Why my task
gulp.task("default", ["clean", "compile", "build"])
is not working?
I have such a task and its not working:
@Task("default")
default() {
return ["clean", "compile", "build"];
}
Why? Because the array you are returning is what task is doing, not a task dependencies as you wish:
@Task("default", ["clean", "compile", "build"])
default() {
}
Samples
This project itself using gulpfile.ts. Take a look on it as an example.