xml-library v0.2.0

XML Library

This Library allows you to convert XML strings into the JSON Format and the other way around.

Installing this Library

Run the following command

$ npm install xml-library --save

Then load it inside your node.js Application

const XML = require('xml-library');

XML (Extensible Markup Language)

Parsing XML

To interpret XML Strings as JSON Objects, you can do

XML.parseXML(xml, function(err, json) {
    // To make sure the parser did not throw any error
    if (!err) {
        // You can now use the 'json' Object to access your XML document
    }
});

For help on how to use the 'json' Object, see XMLNode

Parsing JSON

You can also interpret JSON objects back into XML. BUT: This JSON object must be an XMLNode Object (more Info down below)

'options' (if specified) is a simple JSON Object with keys and values. (Missing keys will be inserted with a default value)

json.asXMLString(options, function(err, xml) {
    // To make sure the parser did not throw any error
    if (!err) {
        // You can now use the 'xml' Object (It is a String)
    }
});

json.asXMLString(function(err, xml) {
    // To make sure the parser did not throw any error
    if (!err) {
        // You can now use the 'xml' Object (It is a String)
    }
});

XMLNode

This module adds a class called "XMLNode". The JSON Object returned when Parsing XML is an instance of this class. Parsing JSON Objects also requires an instance of this class.

You can use the class in your node.js Application using

const XML = require('xml-library');
const XMLNode = XML.XMLNode;

Or by direct deconstruction of the module.

const {XMLNode} = require('xml-library');

Constructor

The constructor requires you to specify a Name for the element.

new XMLNode(name);
new XMLNode("project");

<project></project>

You can also specify attributes.

new XMLNode(name, attributes);
new XMLNode("project", {
    "version": "2.3.1",
    "author": "TheBusyBiscuit"
});

<project version="2.3.1" author="TheBusyBiscuit"></project>

Or you can specify a value.

new XMLNode(name, value);
new XMLNode("project", "XML-Library");

<project>XML-Library</project>

Or a value and attributes.

new XMLNode(name, attributes, value);
new XMLNode("project", {
    "version": "2.3.1",
    "author": "TheBusyBiscuit"
}, "XML-Library");

<project version="2.3.1" author="TheBusyBiscuit">XML-Library</project>

Methods

For the following examples, we work with this node as our root.

var node new XMLNode("project", {
    "version": "2.3.1",
    "author": "TheBusyBiscuit"
});

<project version="2.3.1" author="TheBusyBiscuit"></project>

.addChild(node)

The specified child, must be an instance of XMLNode of course. But it can also be an array of XMLNode instances.

node.addChild(new XMLNode("language", "JavaScript"));

<project version="2.3.1" author="TheBusyBiscuit">
  <language>JavaScript</language>
</project>

.setChild(key, node)

The specified child, must be an instance of XMLNode of course. Because XML elements can have multiple children with the same name, each child needs to have an index. (e.g. language0) This index will be omitted in the actual XML String when Parsing JSON Objects If no index is specified, "0" will be appended to the name.

node.setChild("language", new XMLNode("language", "JavaScript"));
node.setChild("language[1]", new XMLNode("language", "C#"));
node.setChild("language[0]", new XMLNode("language", "Java"));

<project version="2.3.1" author="TheBusyBiscuit">
  <language>Java</language>
  <language>C#</language>
</project>

.setAttribute(key, value)

Pretty self-explaining. Specify a key (String) and a value (String) and set this as an attribute.

node.setAttribute("version", "ALPHA");

<project version="ALPHA" author="TheBusyBiscuit"></project>

If 'value' is null and an attribute with that name exists, then the attribute is removed.

node.setAttribute("version", null);

<project author="TheBusyBiscuit"></project>

.setValue(value)

Pretty self-explaining. Specify a value (String) and you set the inner content of your node. Specify no value and you will remove the inner content of your node (This does not remove any children)

node.setValue("XML-Library");

<project version="2.3.1" author="TheBusyBiscuit">XML-Library</project>

.getChild(path)

Specify the name of a child to get its instance.

<project version="2.3.1" author="TheBusyBiscuit">
  <language>
    <name>Java</name>
  </language>

  <language>C#</language>
</project>

The name can include an index, if there are multiple children sharing the same name.

node.getChild("language[1]");

<language>C#</language>

If no index is specified, it is going to return the first child with that name.

node.getChild("language");

<language>
  <name>Java</name>
</language>

But you can also specify an array of names, to get the node's grandchildren or great grandchildren or ... (You get the idea.)

node.getChild(["language", "name"]);

<name>Java</name>

Here, you can specify an index to target a certain child at a certain point in the tree again.

.asXMLString(options, callback)

See Parsing JSON Objects

Copyright / Licensing

Copyright (c) 2018 TheBusyBiscuit Licensed under the MIT License.